Review Note
Last Update: 04/21/2024 12:02 PM
Current Deck: Mathematik::Basics
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Front
Jounglieren mit Zehnerpotenzen: Finde \(x,y\)
\[0.01 \cdot 10^{-6}=x\cdot 10^{-8}\]\[200 \, 000 \cdot 10^{-10}=y \cdot 10^{-5}\]
\[0.01 \cdot 10^{-6}=x\cdot 10^{-8}\]\[200 \, 000 \cdot 10^{-10}=y \cdot 10^{-5}\]
Back
\[0.01 \cdot 10^{-6}=1\cdot10^{-2}\cdot 10^{-6}=1\cdot 10^{-8}\]\[200 \, 000 \cdot 10^{-10}=2 \cdot10^5\cdot 10^{-10}=2 \cdot 10^{-5}\]
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