Review Note
Last Update: 03/29/2024 09:13 PM
Current Deck: MCAT::General-Chemistry
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Text
For a {{c2::zeroth}} order reaction:
Rate Law: {{c1::\(R=k\)}}
Integrated Rate Law: {{c1::\([A] = [A]_0-kt\)}}
Extra
| Order | Rate Law | Integrated Rate Law* | Half Life | Graph | Units of k |
| Zeroth (0) | \(R = k\) | \([A] = -kt+[A]_0\) | \(t_{\frac{1}{2}}=\frac{[A]_0}{2k}\) | [A] vs. t Slope: \(-k\) Intercept: \([A]_0\) | \(\frac{M}{s}\) |
| First (1) | \(R = k[A]\) | \(ln[A] = -kt+ln[A]_0\) | \(t_{\frac{1}{2}}=\frac{ln(2)}{k}\) | ln[A] vs. t Slope: \(-k\) Intercept: \(ln[A]_0\) | \(\frac{1}{s}\) |
| Second (2) | \(R = k[A]^2\) | \(\frac{1}{[A]} = kt+\frac{1}{[A]_0}\) | \(t_{\frac{1}{2}}=\frac{1}{k[A]_0}\) | \(\frac{1}{[A]}\) vs. t Slope: k Intercept: \(\frac{1}{[A]_0}\) | \(\frac{1}{M\cdot s}\) |
*integrated rate law arranged to resemble equation for straight line y = mx + b
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