Review Note
Last Update: 11/20/2024 07:21 PM
Current Deck: 0) Maths Bridging Programme
PublishedCurrently Published Content
Front
What is the inverse of \[A=\begin{bmatrix}
2 & 1 \\
1 & 4
\end{bmatrix}\]\(det(A)=7\)
Back
\(A^{-1}=\frac17\begin{bmatrix}
4 & -1 \\
-1 & 2
\end{bmatrix}\)
\(B=\begin{bmatrix} a & b \\ c & d \end{bmatrix}\)
\(B^{-1}=\frac{1}{det(B)}\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}\)
\(B=\begin{bmatrix} a & b \\ c & d \end{bmatrix}\)
\(B^{-1}=\frac{1}{det(B)}\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}\)
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