Review Note
Last Update: 12/30/2024 08:30 AM
Current Deck: Physik::T2
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\(x^{\mu}(\tau) \) ein Vierervektor.Was ergibt sich dann für: \(\left\Vert\frac{dx}{d\tau}\right\Vert^2 =\;\; ?\)
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\[\left\Vert\frac{dx}{d\tau}\right\Vert^2
=\ c^2\]
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