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lecture02 - quotient modules
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Published
10/25/2023
When is a subset of R an R-Module
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10/25/2023
If M {{c2::is a free R-module of rank (number of elements in basis) \(n < ∞\)}}, then {{c1::\(M \cong R^n\)}}
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Submodule criterion
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R-submodule of \(M\)
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What do the submodules of \(R\) as an \(R\)-module look like
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10/25/2023
How to find submodules using a homomorphism
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If \(M\) is an \(R\)-module and \(N\) is a {{c1::submodule}}, then the quotient \(M/N\) has an \(R-module\) structure given b…
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10/25/2023
First Isomorphism theorem for modules
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10/25/2023
Suppose \(N⊂M\) is a submodule. What is a good way to think about \(M/N\)?
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submodule generated by a set
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characterizatio of \(<A>\)
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10/25/2023
The R-module homomorphism \(α:N→N_1\) induces a homomorphism \(α_*\)...
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The R-module homomorphism \(α:M→M_1\) induces a homomorphism \(α^*\)...
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10/25/2023
We know that for modules M,N \(Hom_R(M,N)\) is an abelian group. Describe three ways that \(Hom_R(M,N)\) could have a module structure …
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10/25/2023
R-S-bimodule
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R-bimodule
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example: bimodules over subsets of R
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If \(M\) {{c1::is a left R-module}} and N is {{c1::a R-S-bimodule}}, then \(Hom_{R(left)}(M,N)\) is {{c2::a right S-module}} by the formula
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10/25/2023
If \(M\) is {{c1::a R-S-bimodule}} and N is {{c1::a left R-module}}, then \(Hom_{R(left)}(M,N)\) is {{c2::a left S-module}} by the formula
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10/25/2023
bilinear map of modules
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10/25/2023
Is a bilinear map R-linear?
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10/25/2023
Universal property of free modules
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10/25/2023
Construction of the tensor product of R-modules M,N (sketch)1. Take a free module with basis \(M×N\), that is \[F = \bigoplus_{M×N}R\]2. Tak…
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